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The range of values of `a` such that the angle `theta` between the pair of tangents drawn from `(a,0)` to the circle `x^2+y^2=1` satisfies `pi/2 |
Answer» a>1 whe a=1 `theta=2pi/2=pi` `1ltaltsqrt2` `-sqrt2ltalt-1` `a in{(-sqrt2-1)uu(1,sqrt2)}` option b is correct. |
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