1.

The rare law for a reaction between th substances A and B is given by Rate =k[A]^(m)[B]^(n) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

Answer»

`(m+n)`
`(n-m)`
`2^((m-n))`
`(1)/(2^((m+n)))`

ANSWER :C


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