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The rate constant for a first order reaction is 2.3 xx10^(-4)s^(-1). If the initial concentration of the reactant is 0.01M. What concentration will remain after 1 hour? |
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Answer» Solution :Rate constant of a first order REACTION `K = 2.3 xx10^(-4)s^(-1)` Initial concentration of the reactant `[A_0]=0.01M` Concentration will REMAIN after 1 hour [A] = ? `k=(2.303)/TLOG.([A_0])/([A])` `2.3xx10^(-4)=(2.303)/(1"hour")log.([0.01])/([A])` `(2.3xx10^(-4)xx1)/(2.303)=log[0.01]0log[A]` `9.986xx10^(-5)=-2-log[A]` `11.986xx10^(-5)=-log[A]` `[A]="Antilog"(-11.986xx10^(-5))` `[A]=0.9997M` |
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