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| 1. |
The rate constant for a first order reaction is 60 s^(-1). How much time will it take to reduce the initial concentration of the reactant to its 1/16th value ? |
| Answer» Solution :`t=(2.303)/(K)"log"(a)/(a//16)=(2.303)/(60S^(-1))log 16=4.62xx10^(-2)s`. | |