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The rate constant for a first order reaction is 60s^(-1). How much time will it take to reduce the initial concentration of the reactant to its 1//16^(th) value. |
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Answer» Solution :Data : `K = 60S^(-1), [R]_(0) = 1, [R] = (1)/(16) , t = ? ` formlula, `k = (2.303)/(t) log ""([R]_(0))([R])` Substitution : `t = (2.303)/(60) log ""((1)/(1))/(16) rArr t = (2.303)/(60) log 16` `t = (2.303)/(60) xx 1.204 rArr t = 4.6 xx 10^(-2)` seconds. |
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