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The rate constant for a reaction of zero order in A is 0.0030 "mol L"^(-1) s^(-1). How long will it take for the initial concentration of A to fall from 0.10 M to 0.075 M ? |
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Answer» SOLUTION :`[R]t = -K t + [R]_(0)` `0.075 M = -(0.0030 mol L^(-1) s^(-1))t + 0.10 M` `-0.025 M = -(0.003 mol L^(-1) s^(-1))t` `= 8.33 s` |
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