1.

The rate constant for a second order reaction is k=(2.303)/(t(a-b))log""(b(a-x))/((b-x)) where a and b are initial concentrations of the two reactants A and B involved. If one of the reactants is present in excess, it becomes pseudo unimolecular. Explain how ?

Answer»

first order w.r.t. A
zero order w.r.t. A
first order w.r.t.B
overall zero order

Solution :[B](=b), being present in LARGE EXCESS, does not CHANGE practically. The RATE BECOMES independent of [B], i.e., order -0 w.r.t. B.


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