1.

The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2)` and `1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction isA. `4.33`B. `5.33`C. `6.33`D. `7.33`

Answer» Correct Answer - D
`K_(f) = 1.1xx10^(-2), K_(b) = 1.5xx10^(-3)`
`K_(c) = (K_(f))/(K_(b)) = (1.1xx10^(-2))/(1.5xx10^(-3)) = 7.33`


Discussion

No Comment Found

Related InterviewSolutions