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The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2)` and `1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction isA. `4.33`B. `5.33`C. `6.33`D. `7.33` |
Answer» Correct Answer - D `K_(f) = 1.1xx10^(-2), K_(b) = 1.5xx10^(-3)` `K_(c) = (K_(f))/(K_(b)) = (1.1xx10^(-2))/(1.5xx10^(-3)) = 7.33` |
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