The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2) and 1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is `CH_(3)OOC_(2)H_(5)+H_(2)OhArrCH_(3)COOH+C_(2)H_(5)OH`A. `4.33`B. `5.33`C. `6.33`D. `7.33`

The rate constant for forward and backward reactions of hydrolysis of

1.	The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2) and 1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is `CH_(3)OOC_(2)H_(5)+H_(2)OhArrCH_(3)COOH+C_(2)H_(5)OH`A. `4.33`B. `5.33`C. `6.33`D. `7.33`
Answer» Correct Answer - D `K_(f)=1.1xx10^(-2),K_(b)=1.5xx10^(-3)` `K_(c)=(K_(f))/(K_(b))=(1.1xx10^(-2))/(1.5xx10^(-3))=7.33.`

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The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2) and 1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is `CH_(3)OOC_(2)H_(5)+H_(2)OhArrCH_(3)COOH+C_(2)H_(5)OH`A. `4.33`B. `5.33`C. `6.33`D. `7.33`

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