1.

The rate constant for the first order decomposition of H_(2)O_(2) is given by the following equation : log K = 14.2 - (1.0 xx 10^(4))/(T) KCalculate E_a for this reaction and rate constant kif its half life period be 200 minutes. (Given : R = 8.314 JK^(-1) mol^(-1))

Answer»

Solution :log K = 14.2 - `(10^(4)K)/(T)`
Arrhenius equation : `k =Ae^(-Ea//RT)`
log k = log A - `(Ea)/(2.303 RT)`
Compare equation (i) and (II)
= `(cancel(-)Ea)/(2.303 RT) = (cancel(-)10^4)/(cancel(T))`
`Ea = 10^(4) xx 2.303 xx R`
`= 10^(4) xx 2.303 xx 8.314`
Ea = 191.47KJ/mol
`K = (0.693)/(t_(1//2))` [For 1ST order reaction]
`K = (0.693)/(200 xx 60) sec^(-1)`
`K = 5.78 xx 10^(-5)sec-1`


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