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The rate constant `k`, for the reaction `N_(2)O_(5)(g) rarr 2NO_(2) (g) + (1)/(2) O_(2)(g)` is `2.3 xx 10^(-2) s^(-1)`. Which equation given below describes the change of `[N_(2)O_(5)]` with time ? `[N_(2)O_(5)]_(0)` and `[N_(2)O_(5)]_(t)` correspond to concentration of `N_(2)O_(5)` initially and at time, `t` ?A. `[N_(2)O_(5)]_(t) = [N_(2)O_(5)]_(0) + kt`B. `[N_(2)O_(5)]_(0) = [N_(2)O_(5)]_(t)e^(kt)`C. `log_(10) [N_(2)O_(5)]_(t) = log_(10) [N_(2)O_(5)]_(0) - kt`D. In `([N_(2)O_(5)]_(0))/([N_(2)O_(5)]_(t)) = kt` |
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Answer» Correct Answer - D Rate constant `= 2.3 xx 10^(-2) sec^(-1)` It means it is a first order reaction (because unit of rate constant is `sec^(-1)`) For first order reaction`K = (1)/(t)ln(a)/(a-x)` `Kt = ln(a)/(a-x) = ln[N_(2)O_(5)]_(0)/([N_(2)O_(5)]_(x)` |
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