The rate constant of a reaction is 2xx10^(-3) min^(-1) at 300 K temper – InterviewSolution

1.	The rate constant of a reaction is 2xx10^(-3) min^(-1) at 300 K temperature .By increase in temperature by 10 K its value becomes doubl. Calculate energy of activation .Calculation the rate constant at 320 K.
Answer» SOLUTION :`E_(a)`=12810 cal,k(320 K)=`7.659xx10^(-3)min^(-1)`

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