1.

The rate constant of nth order has units:

Answer»

`"litre"^(1-n)MOL^(-1)sec^(-1)`
`mol^(1-n)litre^(1-n)sec`
`mol^(1-n^2)litre^(n^2)sec^(-1)`
`mol^(1-n) litre^(n-1)sec^(-1)`

Solution :For an nth ORDER reaction : RATE = `K [conc.]^n`
`k = ("rate")/(["conc."]^n)`
Units of `k = (mol L^(-1)s^(-1))/((molL^(-1))^n)= mol^(1-n) L^(n - 1) s^(-1)`


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