1.

The rate constants of a reaction at 500 k and 700 k are 0.02"sec"^(-1) and 0.07 "sec"^(-1) respectively. Calculate the value of E_(a)

Answer»

18230.8J
190.83J
185.02J
172.02J

Solution :`(K_(2))/(K_(1))=(Ae^(-Ea_(2)//RT_(2)))/(Ae^(-EA//RT_(1))),0.07/0.02=e^((-epsilon_(a))/(RT_(2))+(epsilon_(a))/(RT_(1)))`
`2.303log(7/2)=(E_(a))/R(1/(T_(1))-1/(T_(2))),2.303xx0.544=(E_(a))/R(1/500-1/700)`
`E_(a)=((2.303xx0.544xx8.314xx500xx700)/200)=18228` Joule


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