1.

The rate for a first order reaction is 0.6932 xx 10^(-2)mol L^(-1) min^-1 and the initial concentration of the reactant is 1 M, t_(1//2) is equal to:

Answer»

`0.6932 X 10^(-2)MINUTE`
`0.6932 x x10^(-2)`
100minute
6.932minute

Answer :C


Discussion

No Comment Found