1.

The rate for the first order reaction is 0.0069 mol L^(-1) min^(-1) and theinitial concentration is 0.2 mol L^(-1) . The half life period is

Answer»

638 s
1205 s
690 s
`0.635 `s

Solution :(B) Rate = K ( C)
`0.0069 mol L^(-1) min^(-1) = (0.2 "mol L"^(-1))` k
`k = (0.0069 )/(0.2)= (3.45xx10^(-2))/(60)`
`= 5.75 xx10^(-4) s^(-1)`
`t_(1//2)=(0.693)/(5.75xx10^(-4)) = 1205 ` s


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