1.

The rate law for a reaction between the substances A and B is given by rate =k[A]^(n)[B]^(m). On doubling the concentration of A and having the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be

Answer»

`m+n`
`n-m`
`2^((n-m))`
`(1)/(2^((m+n)))`

ANSWER :C


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