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The rate law for the reaction 2H_(2(g))+2NO_((g)) to N_(2(g))+2H_(2)O_((g)) is given by rate =-=k[H_(2)][NO]^(2) The reaction occurs in the following two steps: (a) H_(2(g))+2NO_((g)) to N_(2)O_((g))_H_(2)O_((g)) N_(2)O_((g))+ H_(2(g)) to N_(2(g))+H_(2)O_((g)) What is the rate of N_(2)O in the mechanism ? What is the molecularity of each of the elementary stpes ? |
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Answer» SOLUTION :Rate of `N_(2)O=K[N_(2)O][H_(2)O]` Molecularity for 1ST STEP is 3 Molecularity for 2nd step is 2. |
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