1.

The rate of a first order reaction is 0.04 mol l^(-1) s^(-1) at 10 seconds and 0.03 mol l^(-1) s^(-1) at 20 seconds after initiation of the reaction . The half-life period of the reaction is

Answer»

24.1 s
34.1 s
44.1 s
54.1 s

Solution :`K = (2.303)/((t_(2) - t_(1))) "log" ((a-x_(1)))/((a-x_(2))) K = (2.303)/((20-10)) "log" ((0.04)/(0.03))`
`K = (2.303 XX 0.1249 )/(10) (2.303 xx "log" 2)/(t_(1//2) = (2.303 xx "log" 2)/(10)`
`t_(1//2) = (0.3010 xx 10)/(0.1249) = 24.1` SEC


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