1.

The rate of a gaseous reaction is given by the is expression k[A][B].If the volume of the reaction vessel is suddenly reduced to 1//4 of the initial volume, the reaction rate relating to original rate will be

Answer»

`1//10`
`1//8`
8
16

Solution :SINCE active mass = CONCENTRATION in moles/litre Thus when the volume of the reaction vessel reduces to `1/4^(th)` of its initial volume the molar concentration of each REACTANT increases four times. Thus
r=K[4A][4B]-16 k [A][B] i.e. 16 times.


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