1.

The rate of a reaction doubles when its temperature changes from 300 K to 310 K.Activation energy of such a reaction will be: (R=8.314 JK^(-1)mol^(-1) and log 2=0.301)

Answer»

53.6 KJ `MOL^(-1)`
48.6 KJ `mol^(-1)`
58.5 KJ `mol^(-1)`
60.5 KJ `mol^(-1)`

ANSWER :A


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