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InterviewSolution
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The rate of a reaction increases four-fold when the concentration of reactant is increased `16` times. If the rate of reaction is `4 xx 10^(-6) mol L^(-1) s^(-1)` when the concentration of the reactant is `4 xx 10^(-4) mol L^(-1)`. The rate constant of the reaction will beA. `2 xx 10^(-4) mol^(1//2) L^(1//2) s^(1//2)`B. `1 xx 10^(-2) s^(-1)`C. `2 xx 10^(-4) mol^(-1//2) L^(1//2) s^(-1)`D. `25 mol^(-1) L min^(-1)` |
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Answer» Correct Answer - A Rate`prop sqrt("Concentration") = ksqrt("Concentration")` `k = (Rate)/("Concentration")^(1//2)` `= (4 xx 10^(-6))/(4 xx 10^(-4))^(1//2) = (4 xx 10^(-6))/(2 xx 10^(-2)) = 2 xx 10^(-4) mol^(1//2) L^(-1//2) s^(-1)` |
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