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The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature. |
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Answer» T1 = 293K, T2 = 313K According to Arrhenius equation, \(log\frac{k_2}{k_1}=\frac{E_a}{2.303\,R}[\frac{T_2\,-\,T_1}{T_1\,T_2}]\) ∴ Ea = 2.303 R x \([\frac{T_1\,T_2}{T_2\,-\,T_1}]log\frac{k_2}{k_1}\) ∴ Ea = 2.303 R x 8.314 JK-1mol-1 x \([\frac{293\,\times\,313}{313\,-\,293}]log\frac{4}{1}\) 2.303 × 8.314 J K-1 mol-1 × 4585.45 K × 0.6021 = 52863.33 J mol-1 = 52.86 kJ mol-1 |
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