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The rate of cooling at 600 K, if surrounding tempearture is 300 K is R. The rate of cooling at 900 K is : |
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Answer» `16/3R` `:.(E_(2))/(E_(1))=((900)^(4)-(300)^(4))/((600)^(4)-(300)^(4))` `(E_(2))/(E_(1))=(9^(4)-3^(3))/(6^(4)-3^(4))=(16)/(3)rArrE_(2)=(16)/(3)E_(1)=(16)/(3)R`. CORRECT CHOICE is (a). |
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