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The rate of emission of heat energy of an iron ball of radius 5 cm is 10 J/s, then rate of emission of heat energy by a copperr ball of radius 1 cm at same temperature will be (If emissivity of both the balls is same)A. 2 J/sB. 0.4 J/sC. 2 cal/sD. 250 J |
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Answer» Correct Answer - B `(R_(2))/(R_(1))=(A_(2))/(A_(1))((T_(2))/(T_(1)))^(4)` as `T_(1)=T_(2)` `(R_(2))/(R_(1))=(1)/(25)` `therefore R_(2)=(10)/(25)=0.4J//s` |
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