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The rate of formation of a dimer in a second order reaction is 7.5 x 10-3 mol L-1 s-1 at 0.05 mol L-1 monomer concentration. Calculate the rate constant. |
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Answer» Let us consider the dimensation of a monomer M 2M → (M)2 Rate = k [M]n Given that n =2 and [M] = 0.05 mol L-1 Rate = 7.5 x 10-3 mol L-1 s-1 Rate 7.5 x 103 mol L-1 s-1 k = \(\frac{Rate}{[M]^n}\) k = \(\frac{7.5\times10^{-3}}{(0.05)^2}\) = 3 mol-1 Ls-1 |
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