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The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. `K_(equilibrium)` isA. `2.5`B. `2.0`C. `0.5`D. `1.5`

Answer» Correct Answer - B
The rate of forward reaction is two times that of reverse reaction at a gives temperature and identical concetration `K_(equilibrium)` is 2 because the reaction is revessible. So `K = (K_(1))/(K_(2)) = (2)/(1) = 2`


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