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The rate of forward reaction is two times that of reverse reaction at a given temperaturee and identical concentration. `K_("equilibriuim")` isA. `2.5`B. `2.0`C. `0.5`D. `1.5` |
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Answer» Correct Answer - B The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration `K_("equlibrium")` is 2 because the reaction is reversible. So `K=(K_(1))/(K_(2))=2/1=2.` |
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