1.

The rate of loss of heat by radiation frombody at 400^(@)C is R. then radiation from it when the temperature of the ball is 627^(@)C. Then the rate of loss of heat per unit area will be

Answer»

2R
4R
3/16 R
16/3 R

Solution :`(R_(2))/(R_(1))=((T_(2))/(T_(1)))^(4)=((1073)/(673))^(4)=(1.5)^(4)=(81)/(16)=5`
`R_(2)=5R`.


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