1.

The rate of reaction. 2N_(2)O_(5) to 4NO_(2) + O_(2) can be written in three ways. (-d[N_(2)O_(5)])/(dt) = k[N_(2)O_(5)] (d[N_(2)O_(5)])/(dt) =( k^(')[N_(2)O_(5)]) (d[O_(2)])/(dt) = (k^(')[N_(2)O_(5)]) The relation between k and k^(') are:

Answer»

k=k
2k=k
k=2k'
k=4k'

Solution :Rate of DISAPPEARANCE of reactant = Rate of appearance of PRODUCTS
`(1)/(2)(d[N_(2)O_(5)])/(DT)=(1)/(4)(d[NO_(2)])/(dt)`
`(1)/(2)k[N_(2)O_(5)]=(1)/(4) k.[N_(2)O_(5)]`
`(k)/(2)=(k.)/(4), :. k.=2k`


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