1.

The rate of the reaction A rarr Products at the initial concentration of 3.24 xx10^(-2) M is nine times its rate at another initial concentration of 1.2xx10^(-3) M. The order of the reaction is

Answer»

`(1)/(2)`
`(3)/(4)`
`(2)/(3)`
`(3)/(2)`

Solution :( C) If rate at conc .` 1.2 xx10^(-2) ` M is r then
`r = k(1.2xx10^(-3))^(a)"" cdots(i) `
`9r= k(3.24xx10^(-2))^(a) "" cdots(II)`
DIVIDING eq (ii) by eq. (i)
`9=((3.24xx10^(2))^(a))/((1.2xx10^(-3))^(a))=27^(a)`
or` 3^(2)=3^(3A)`
`:. 3a=2 "or" a =2//3`


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