1.

The rate of the reaction X rarrY becomes 8 times when the concentration of the reactant 'X' is doubled . The rate law of the reaction is ............

Answer»

`-(d[X])/(dt)=K[X]^2`
`-(d[x])/(dt)=k[X]^3`
`-(d[x])/(dt)=k[X]^4`
`-(d[x])/(dt)=k[X]^8`

ANSWER :B


Discussion

No Comment Found

Related InterviewSolutions