1.

The ratio between the first three orbits of hydrogen atom is

Answer»

`1 : 2 : 3`
`2 : 4 : 6`
`1 : 4 : 9`
`1 : 3 : 5`

SOLUTION :`E_(n) = (-13.6 xx Z^(2))/(n^(2)) (EV)/(atom)`
`n = 1, E_(1) = -13.6 (eV)/(atom)`
`n = 2,E_(2) = -3.4 (eV)/(atom)`
`n = 3, E_(3) = -1.51 (eV)/(atom)`
The ratio of THREE orbits
`E_(1) : E_(2) : E_(3) = 13.6 : 3.4 : 1.51`
`= 1 : 4 : 9`


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