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The ratio between the root mean square speed of `H_(2)` at `50 K` and that of `O_(2)` at `800 K` isA. 4B. 2C. 1D. `1//4` |
Answer» Correct Answer - c (c) `U_("ms")=sqrt((3RT)/(Mw))` `(U_(H_(2)))/(U_(O_(2)))=sqrt((50)/(2)xx(32)/(800))=1` |
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