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The ratio of AM and GM of two positive numbers a and b is m:n, show that: a:b=(m+\surd m²-n²):(m-\surd m²-n²

Answer» The ratio of AM and GM of two positive numbers a and b is m:n, show that: a:b=(m+\surd m²-n²):(m-\surd m²-n²


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