The ratio of angular speed of a second- hand to the hour-hand of a wat

1.	The ratio of angular speed of a second- hand to the hour-hand of a watch is
Answer» `72: 1` `3600: 1` `60: 1` `720: 1` Solution :`omega= (theta)/(t) rArr omega alpha (1)/(t)` HENCE `(omega_(sec))/(omega_("hour"))= (t_("hour"))/(t_(sec))= (12 xx 3600s)/(60S)= 720 THEREFORE omega_(sec): omega_("hour") = 720: 1`

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The ratio of angular speed of a second- hand to the hour-hand of a watch is

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