1.

The ratio of close packed atoms to tetahedral hole in cubic packing is ………….

Answer»

`1:1`
`1:2`
`2:1`
`1:4`

Solution :Hint : If number of CLOSE packed = N , then,
The number of TETRAHEDRAL holes formed = 2N
Number of OCTAHEDRAL holes formed = N. THEREFORE `N:2N=1:2`


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