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The ratio of contributions made by the electric field and magnetic field components to the intensity of the EM wave is……… |
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Answer» `C:1` `I_m=(B_(rms)^2)/(mu_0)c` `THEREFORE I_e/I_m=(E_(rms)/B_(rms))^2mu_0epsi_0=c^2 times 1/c^2=1 IMPLIES 1_e=I_m` |
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