1.

The ratio of contributions made by the electric field and magnetic field components to the intensity of the EM wave is………

Answer»

`C:1`
`C^2:1`
`1:1`
`sqrtC:1`

Solution :`I_e=epsi_0E_(RMS)^2C`
`I_m=(B_(rms)^2)/(mu_0)c`
`THEREFORE I_e/I_m=(E_(rms)/B_(rms))^2mu_0epsi_0=c^2 times 1/c^2=1 IMPLIES 1_e=I_m`


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