Saved Bookmarks
| 1. |
The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is |
|
Answer» `c:1` Intensity due to MAGNETIC field `I_B=(cB^2)/(2mu_0)` `I_E/I_B=(1/2cepsilon_0E^2)/(cB^2//2mu_0)=(epsilon_0mu_0)(E//B)^2=(1/c^2)(c^2)=1` (as `c=1/sqrt(epsilon_0mu_0` and E/B=c ) |
|