1.

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is

Answer»

`c:1`
`c^2:1`
`1:1`
`sqrtc:1`

SOLUTION :As intensity due to electric FIELD `I_E=1/2 cepsilon_0E^2` ,
Intensity due to MAGNETIC field `I_B=(cB^2)/(2mu_0)`
`I_E/I_B=(1/2cepsilon_0E^2)/(cB^2//2mu_0)=(epsilon_0mu_0)(E//B)^2=(1/c^2)(c^2)=1` (as `c=1/sqrt(epsilon_0mu_0` and E/B=c )


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