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The ratio of diameters of two wires of same material is `n:1`. The length of each wire is `4 m`. On applying the same load, the increases in the length of the thin wire will be `(n gt 1)`A. `n^(2)` tiemsB. `n` timesC. `2n` timesD. `(2n + 1)` times |
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Answer» Correct Answer - A `e = (Fl)/(pi r^(2)Y), F alpha r^(2)` |
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