1.

The ratio of energy of emitted radiation of a black body at 27^(@)C and 927^(@)C is :

Answer»

`1:4`
`1:16`
`1:64`
`1:256`

Solution :`(E_(1))/(E_(2))=((T_(1))/(T_(2)))^(4)=((27+273)/(927+273))^(4)`
`(E_(1))/(E_(2))=((1)/(4))^(4)""RARR(E_(1))/(E_(2))=(1)/(256)`
Thus CORRECT CHOICE is (d).


Discussion

No Comment Found

Related InterviewSolutions