InterviewSolution
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InterviewSolution
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The ratio of energy required to raise a satellite to a height `h` above the earth surface to that required to put it into the orbit isA. `h:2R`B. `2h:R`C. `R:h`D. `h:R` |
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Answer» Correct Answer - B `E_(1)=triangleU=(mgh)/(1+h//R)` `E_(2)` = Energy of satellite -Energy of satellite on surface of earth `=-(GMm)/(2(R+h)+(GMm)/(R )=mgR[1-(1)/2(1+(h)/(R ))]` `therefore =(mgh)/(1+(h)/(R ))xx2(1+(h)/(R ))/(mgR)=(2h)/(R )` |
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