InterviewSolution
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InterviewSolution
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The ratio of energy required to raise a satellite to a height `h` above the earth surface to that required to put it into the orbit isA. `2h:R`B. `h:2R`C. `R:h`D. `h:R` |
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Answer» Correct Answer - A For a satellite at a height h, `U_(h)=-(GMm)/(R+h)` and on the surface of the earth `U_(E )=-(GMm)/(R )` `therefore E_(1)=Delta U=(-(GMm)/(R+h))-(-(GMm)/(R ))` `=(GMm)/(R )-(GMm)/(R+h)=(GMmh)/(R(R+h))` and the energy required to put it in the orbit `E_(2)=(1)/(2)mv_(0)^(2)=(1)/(2)m((GM)/(R+h))` `therefore (E_(1))/(E_(2))=(GMmh)/(R(R+h))xx(2(R+h))/(GMm)=(2h)/(R )` |
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