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The ratio of escape velocity at earth `(v_(e))` to the escape velocity at a planet `(v_(y))` whose radius and density are twiceA. `1:sqrt(2)`B. `1:2`C. `1:2sqrt(2)`D. `1:4` |
Answer» Correct Answer - C `ve=sqrt((2GM)/R) =sqrt((2G)/R. (4/3 piR^(3) rho)) prop Rsqrt(rho)` `:. Ratio =1:2sqrt(2)` |
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