The ratio of he areas of triangle ADC and triangle BDC is – InterviewSolution

1.	The ratio of he areas of triangle ADC and triangle BDC is
Answer» Let ABC is a ∆ WHOSE BASE is AB . D is a point on AB such that AB=5cm and DB=3cm. Thus AD=AB-DB= 5–3 =2cm. Join C to D . DRAW a perpendicular CP on AB . AREA of ∆ ADC/Area of ∆ABC. = 1/2×CP×AD/1/2×CP×AB. =AD/AB =2cm/5cm =2/5. or. 2 : 5. AnswerStep-by-step EXPLANATION:

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