1.

The ratio of K.E. regd. to be given to satellite to escape earth's gravitational field to K.E. regd. to be given to satellite to move in a circular orbit just above earth's atmosphere is :

Answer»

1
2
0.5
infinity.

Solution :`v_(e )=sqrt(2gR), v_(0)=sqrt(GR)`.
`therefore ((1)/(2)mv_(e)^(2))/((1)/(2)mv_(0)^(2))=((v_(e))/(v_(0)))^(2) =(sqrt(2))^(2)=2`
So the CORRECT choice is (B).


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