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The ratio of kinetic energy of the total energy of an electron of a Bohr orbit of the hydrogen atom is ...... |
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Answer» Solution :Kinetic energy `K=(1)/(8pi epsi_(0))*(Ze^(2))/(r)` Total energy `E_(n)=-(1)/(8pi epsi_(0))*(Ze^(2))/(r)` `:.(K)/(E_(n))=-1` |
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