1.

The ratio of longest wavelength and the shortest wavelength as observed in the five spectral series of emission spectrum of hydrogen is:

Answer»

`4/3`
`(525)/(376)`
25
`(900)/(11)`

Solution :For Lyman series
`1/lambda =R [1/1^(2)-1/n^(2)]`
`lambda " SHORTEST" =1/R" as n="oo`
For Pfund SEREIS `1/lambda =R[1/5^(2)-1/n^(2)]`
`((1)/(lambda_("longest")))=R/(25)-(R)/(36)`
As n=6
`(lambda_("longest"))/(lambda_("shortest"))=(25 xx 36)/(11R) xx R=(900)/(11)`


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