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The ratio of longest wavelength and the shortest wavelength observed in the 5 spectral series of emission spectrum of hydrogen is ....... |
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Answer» `(4)/(3)` `"ln" (1)/(lambda)=R[(1)/(m^(2))-(1)/(n^(2))], m=5 and n=6` `:. (1)/(lambda_(F))=R[(1)/(5^(2))-(1)/(6^(2))]` `:. (1)/(lambda_(F))=(11R)/(900)` `:. (1)/(lambda_(F))=(900)/(11R)...(1)` For shortest wavelength in LYMAN series m=1 and `n=oo` `:. (1)/(lambda_(L))=R[(1)/(1^(2))-(1)/(oo^(2))]=(R)/(1)` ` :. (1)/(lambda_(L))=(1)/(R) ...(2)` `RARR` Ratio `=(lambda_(F))/(lamda_(L))=(900)/(11R)xx(R)/(1)=(900)/(11)` |
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