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The ratio of longest wavelength and the shortest wavelength observed in the five spectral series of emission spectrum of hydrogen isA. `(4)/(3)`B. `(525)/(376)`C. `25`D. `(900)/(11)` |
Answer» Correct Answer - D Shortest wavelength comes from `n_(1) = oo` to `n_(2) = 1` and longest wavelength comes from `n_(1) = 6` to `n_(1) = 5` in the given. Case. Hence `(1)/(lambda_(min)) = R ((1)/(1^(2)) - (1)/(oo^(2)))= R` `(1)/(lambda_(max)) = R ((1)/(5^(2)) - (1)/(6^(2)))= R ((36 - 25)/(25 xx 36)) = (11)/(900)R` `:. (lambda_(max))/(lambda_(min)) = (900)/(11)` |
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